Brain Test All-Star Timing

Brain Test All-Star Level 171: Bring them together.

Brain Test All-Star Level 171

Medium

Screenshots

Brain Test All-Star Level 171 screenshot 1Brain Test All-Star Level 171 screenshot 2
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Quick Answer

Drag the rock to block the woman's movement, then swipe the screen to move both characters until they meet in the same square.

Skills Tested

AttentionObservationSpatial Thinking

Step-by-Step Solution

  1. 1) Drag the rock in front of the woman to block her path.
  2. 2) Swipe the screen to move the characters around.
  3. 3) Keep guiding them until they both land in the same square.

Hint

Reveal a hint

Someone is moving too fast to catch. Slow her down first, then guide both into one spot.

Why It Works

This puzzle is all about timing and control. The rock acts as a blocker so the woman cannot slip away, which gives you a clear chance to swipe both characters toward the exact same square.

Frequently asked questions

How do I bring the characters together in Brain Test All-Star Level 171?

Drag the rock to block the woman first, then swipe the screen to move both characters until they meet in the same square.

What is the answer to Brain Test All-Star Level 171?

Block the woman with the rock, then swipe the screen so both characters end up together on the same square.

What is the trick in Brain Test All-Star Level 171?

You cannot catch her by chasing. The hidden move is using the rock as a blocker to stop the woman so you can guide both into one tile.

Why do I need to block the woman with a rock in Brain Test All-Star Level 171?

The woman keeps moving away, so the rock stops her and gives you the chance to swipe both characters together.

Is there a video walkthrough for Brain Test All-Star Level 171?

Yes. The embedded video shows dragging the rock and swiping to bring both characters together.

How do I avoid getting stuck in Brain Test All-Star Level 171?

Place the rock in the woman path first, then swipe slowly and steadily so both characters converge on the same square without overshooting.